A good way to proceed is to find the normal vector to the plane nabc and then the equation by. This equation will result in a circle with the center at h k and the radius measures r. Yet Another Important Problem In 3 Dimensional Geometry Again We Use The Cartesian Equation Form To Find The Solution As That Is So Ea Mathematics Lines Math A. . Ax By Cz D 0 where vector A B C is the normal to the plane. We know the equation of any plane passing through the first point is. Ax-x_0by-y_0cz-z_00 To find the normal nabc lets consider that it has to be orthogonal both to AB and to the normal vector to the given plane m12-1. Xyz are the coordinates of the point on a plane and d is the distance of the plane from the origin. X 1 y 1 z 1 are the coordinates of the point on a plane. Planes also have a third form of representation namely the cartesian equation. D r. The Cartesian equation of a plane is a x. 6 rows How ...